4x+2[4-2(x-2)]=2x-4

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Solution for 4x+2[4-2(x-2)]=2x-4 equation: 


Simplifying
4x + 2[4 + -2(x + -2)] = 2x + -4

Reorder the terms:
4x + 2[4 + -2(-2 + x)] = 2x + -4
4x + 2[4 + (-2 * -2 + x * -2)] = 2x + -4
4x + 2[4 + (4 + -2x)] = 2x + -4

Combine like terms: 4 + 4 = 8
4x + 2[8 + -2x] = 2x + -4
4x + [8 * 2 + -2x * 2] = 2x + -4
4x + [16 + -4x] = 2x + -4

Reorder the terms:
16 + 4x + -4x = 2x + -4

Combine like terms: 4x + -4x = 0
16 + 0 = 2x + -4
16 = 2x + -4

Reorder the terms:
16 = -4 + 2x

Solving
16 = -4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
16 + -2x = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
16 + -2x = -4 + 0
16 + -2x = -4

Add '-16' to each side of the equation.
16 + -16 + -2x = -4 + -16

Combine like terms: 16 + -16 = 0
0 + -2x = -4 + -16
-2x = -4 + -16

Combine like terms: -4 + -16 = -20
-2x = -20

Divide each side by '-2'.
x = 10

Simplifying
x = 10

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